HttpClient with java Socket possible to achieve a mistake
A java Socket HttpClient possible to achieve a mistake
Import java.io.ByteArrayOutputStream;
Import java.io.IOException;
Import java.net.Socket;
Import java.net.UnknownHostException;
(Public class test2
Public static void main (String arg []) throws Exception
(
Try (
Socket socket = new Socket ( "www.baidu.com," 80);
Byte [] bytes = ( "GET / HTTP/1.1 \ n" +
"Host: www.baidu.com \ n" +
"Connection: close \ n" +
"User-agent: Mozilla/4.0 \ n" +
"Accept-language: zh-cn \ n" +
"\ N"). GetBytes ( "UTF-8");
Socket.getOutputStream (). Write (bytes);
ByteArrayOutputStream arrayOutputStream = new ByteArrayOutputStream (8192);
Int c;
While ((c = socket.getInputStream (). Read ())! = -1) (
ArrayOutputStream.write (c);
)
System.out.println (new String (arrayOutputStream.toByteArray ()));
) Catch (UnknownHostException e) (
E.printStackTrace ();
) Catch (IOException e) (
E.printStackTrace ();
)
)
)
Note that if written GET Get some sites may not have the http documents, such as www.baidu.com
Tags: java httpclient, java socket, Socket